Question

factorise x⁴ + x² + 1​

Answer 1

Step-by-step explanation:

Consider

x4 + x2 + 1 = (x4 + 2x2 + 1) – x2

= [(x2)2 + 2x2 + 1] – x2

= [x2 + 1]2 – x2

It is in the form of (a2 – b2) = (a + b)(a – b)

Hence [x2 + 1]2 – x2 = [x2 + 1 + x] [x2 + 1 – x]

Answer 2

Answer:

Given ,

${x}^{4} + {x}^{2} + 1 \\ \\ = ( {x}^{2} )^{2} + 2( {x}^{2} )(1) + {1}^{2} - {x}^{2} \\ \\ = ( {x}^{2} + 1) ^{2} - {x}^{2} \\ \\ = ( {x}^{2} + 1 - x)( {x}^{2} + 1 + x)$

hope this much helps uh ❣️