factorise x⁴ + x² + 1
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Answer:
Consider x^4 + x^2 + 1
= (x^4 + 2x^2 + 1) – x^2
= [(x2)^2 + 2x^2 + 1] – x^2
= [x^2 + 1]^2 – x^2
It is in the form of (a^2 – b^2) = (a + b)(a – b)
Hence [x2 + 1]^2 – x^2 = [x^2 + 1 + x] [x^2 + 1 – x]
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