Factorise : x⁴+x²y²+y⁴
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Answer:
This can be factored by completing the square.
Recall that perfect square trinomial x²+2xy+y² = (x+y)².
x⁴ + x²y² +y⁴ first term and 3rd term are perfect squares
= (x²)² + x²y² + (y²)² the middle term should to be 2x²y² to make
it a perfect square, so add x²y² - x²y²
= (x²)² + x²y² + (y²)² + x²y² - x²y² combine 2nd and 4th terms
= (x²)² + 2 x²y² + (y²)² - x²y² first 3 terms form a perfect square trionomial
= (x² + y²)²- (xy)² it is a difference of two squares, now factor
=(x² + y² + xy)(x² + y² - xy)
Hope it helps you my dear friend..
Step-by-step explanation:
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Answered by
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Hello
To factorise - x^4+x^2y^2+y^4
x^4+x^2y^2+y^4
(x^2)^2 +x^2y^2+(y^2)^2
We know that (a+b)^2 = a^2 + b^2 + 2(a)(b)
= (a+b)^2 - ab = a^2 + b^2 + ab
Here a= x^2 and b= y^2
So we conclude by
(x^2 + y^2)^2 - x^2y^2
To factorise - x^4+x^2y^2+y^4
x^4+x^2y^2+y^4
(x^2)^2 +x^2y^2+(y^2)^2
We know that (a+b)^2 = a^2 + b^2 + 2(a)(b)
= (a+b)^2 - ab = a^2 + b^2 + ab
Here a= x^2 and b= y^2
So we conclude by
(x^2 + y^2)^2 - x^2y^2
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