Question

Factorise x⁴ - (y+z)⁴​

Answer 1

$\huge{\fcolorbox{cyan} {black} {\green{verified✓}}}$

$\huge{\fcolorbox{cyan} {black} {\pink{Answer}}}$

In this question, we only use the identity [a² - b² = (a + b)(a - b)]

x⁴ - (y+z)⁴

= (x²)² - {(y+z)²}²

= {x² + (y+z)²}{x² - (y+z)²}

= {x² + y² + z² + 2yz}{x + (y+z)}{x - (y+z)}

= (x² + y² + z² + 2yz)(x + y + z)(x - y - z)

Answer 2

Answer:

In this question, we only use the identity [a² - b² = (a + b)(a - b)]

x⁴ - (y+z)⁴

= (x²)² - {(y+z)²}²

= {x² + (y+z)²}{x² - (y+z)²}

= {x² + y² + z² + 2yz}{x + (y+z)}{x - (y+z)}

= (x² + y² + z² + 2yz)(x + y + z)(x - y - z)