factorise x⁴- (y+z)⁴
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2
Step-by-step explanation:n this question, we only use the identity [a² - b² = (a + b)(a - b)]
x⁴ - (y+z)⁴
= (x²)² - {(y+z)²}²
= {x² + (y+z)²}{x² - (y+z)²}
= {x² + y² + z² + 2yz}{x + (y+z)}{x - (y+z)}
answer is
[a² - b² = (a + b)(a - b)]
x⁴ - (y+z)⁴
Answered by
0
Answer:
(x² + y² + z² +2yz)(x² - y² - z² - 2yz)
Step-by-step explanation:
x⁴- (y+z)⁴
= (x²)² - [(y+z)²]²
= [ x² + (y+z)² ]*[ x² - (y+z)² ]
= (x² + y² + z² +2yz)(x² - (y² + z² +2yz))
= (x² + y² + z² +2yz)(x² - y² - z² - 2yz)
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