Factorise x⁶+3x³-28
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x^6+3x^3-28
=x^6+7x^3-4x^3-28
=(x^6+7x^3)-(4x^3+28)
=x^3(x^3+7)-4(x^3+7)
=(x^3+7)(x^3-4)
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=x^6+7x^3-4x^3-28
=(x^6+7x^3)-(4x^3+28)
=x^3(x^3+7)-4(x^3+7)
=(x^3+7)(x^3-4)
Please mark me brainliest if you like my answer as it is very urgent.
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