Math, asked by vivekGHATE, 2 months ago

Factorise x8

– 1 completely.​

Answers

Answered by samaira173
1

Answer:

(x^4+1 )(x^2+1)(x+1)(x-1)

Step-by-step explanation:

x^8 - 1

=(x4)^2 - (1)^2

=(x^4 +1)(x^4-1)

=(x^4+1)((x^2)^2-(1)^2)

=(x^4+1 )(x^2+1)(x^2-1)

=(x^4+1 )(x^2+1)((x)^2-(1)^2)

=(x^4+1 )(x^2+1)(x+1)(x-1)

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