Question

factorise x⁸+1. ..............................pls dont spam.​

Answer 1

Answer:

${x}^{8} + 1 \\ = > {x}^{5} \times {x}^{3} + 1\\ = > {x}^{5} \times {x}^{3} + {1}^{3} \\ = > {x}^{5} \times {x}^{2} + {1}^{2} + 3 \times {x}^{2} \times 1 + 3 \times x + {1}^{2} \\ = > {x}^{5} \times {x}^{2} + 4 \times {x}^{2} + 4 \times x + 1 \\ = > x( {x}^{4} \times x \times x \times 1) + 4 + 4 + 1 \\ = > {x}^{5} \times {x}^{2} + 9$

used formula:-a^3+b^3=a^2+b^2+3a^2b+3ab^2

Step-by-step explanation:

hope it Helps you