factorise xcube-3xsqure-9x-5
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Answer:
we are putting x=1
sol. = 1-3-9-5 = -16 is not eql to 0.
x= -1
-1 -3 +9 -5 = 0
hence x= -1 is one sol. of our cubic eqn.
now divide by x + 1
divident =
sol. of eqn. x-5 nd x+1
hence all three sol. of eqn are:- x=-1 , x = 5 , x = -1
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