Factorise: xcube+6xsquare+11x+6
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the factors of 6 are +1,-1+2,-2,+3,-3
by trail method:x=-1
x³+6x²+11x+6=(-1)³+6(-1)²+11(-1)+6
=-1+6-11+6
=-12+12
=0
therefore(x+1)is the factor
by the process of long dividion we get the polynomial x²+5x+6
then by factorising we get (x+2) (x+3).
therefore(x+1) (x+2) (x+3) are the factors
by trail method:x=-1
x³+6x²+11x+6=(-1)³+6(-1)²+11(-1)+6
=-1+6-11+6
=-12+12
=0
therefore(x+1)is the factor
by the process of long dividion we get the polynomial x²+5x+6
then by factorising we get (x+2) (x+3).
therefore(x+1) (x+2) (x+3) are the factors
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