Question

factorise xsquare-x-4

Answer 1

Solution:

Given, x^2-x-4 =0

here,a=1,b= -1,c= -4

Therefore,

$x = \frac{ - b + or - \sqrt{b^{2} - 4ac} }{2a}$

$\: \: \: = \frac{ - 1 + or - \sqrt{( - 1)^{2} - 4( - 4)} }{2}$

$\: \: \: = \frac{ - 1 + or - \sqrt{1 + 16} }{2}$

$\: \: \: = \frac{ - 1 + or - \sqrt{17} }{2}$