Question

factorise (y+1)³-(y-1)³. if you answer correctly I will Mark you as brainlist​

Answer 1

Step-by-step explanation:

$(y + 1) {}^{3} - (y - 1) {}^{3} \\ = y {}^{3} + 3y {}^{2} + 3y + 1 - (y {}^{3} - 3y {}^{2} + 3y - 1) \\ = y {}^{3} + 3y {}^{2} + 3y + 1 - y {}^{3} + 3y {}^{2} - 3y + 1 \\ = 6y {}^{2} + 2$