Factorise y^(2)+1-2y
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Answer:
y² - 2y + 1 = 0
⇒ y² -y -y + 1 = 0
⇒ y(y - 1) - (y - 1) = 0
⇒ (y - 1) × (y - 1) = 0
⇒ y - 1 = 0
⇒ y = 1
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