Question

Factorise y^2+10y+21 using factor theorem?​

Answer 1

Answer:

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Step-by-step explanation:

Factoring y2-10y+21

Factoring y2-10y+21 Step-1 : Multiply the coefficient of the first term by the constant 1 • 21 = 21

Factoring y2-10y+21 Step-1 : Multiply the coefficient of the first term by the constant 1 • 21 = 21 Step-2 : Find two factors of 21 whose sum equals the coefficient of the middle term, which is -10 .

Factoring y2-10y+21 Step-1 : Multiply the coefficient of the first term by the constant 1 • 21 = 21 Step-2 : Find two factors of 21 whose sum equals the coefficient of the middle term, which is -10 . -21 + -1 = -22

Factoring y2-10y+21 Step-1 : Multiply the coefficient of the first term by the constant 1 • 21 = 21 Step-2 : Find two factors of 21 whose sum equals the coefficient of the middle term, which is -10 . -21 + -1 = -22 -7 + -3 = -10 That's it

Factoring y2-10y+21 Step-1 : Multiply the coefficient of the first term by the constant 1 • 21 = 21 Step-2 : Find two factors of 21 whose sum equals the coefficient of the middle term, which is -10 . -21 + -1 = -22 -7 + -3 = -10 That's itStep-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -7 and -3

Factoring y2-10y+21 Step-1 : Multiply the coefficient of the first term by the constant 1 • 21 = 21 Step-2 : Find two factors of 21 whose sum equals the coefficient of the middle term, which is -10 . -21 + -1 = -22 -7 + -3 = -10 That's itStep-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -7 and -3 y2 - 7y - 3y - 21

Factoring y2-10y+21 Step-1 : Multiply the coefficient of the first term by the constant 1 • 21 = 21 Step-2 : Find two factors of 21 whose sum equals the coefficient of the middle term, which is -10 . -21 + -1 = -22 -7 + -3 = -10 That's itStep-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -7 and -3 y2 - 7y - 3y - 21Step-4 : Add up the first 2 terms, pulling out like factors :

Factoring y2-10y+21 Step-1 : Multiply the coefficient of the first term by the constant 1 • 21 = 21 Step-2 : Find two factors of 21 whose sum equals the coefficient of the middle term, which is -10 . -21 + -1 = -22 -7 + -3 = -10 That's itStep-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -7 and -3 y2 - 7y - 3y - 21Step-4 : Add up the first 2 terms, pulling out like factors : y • (y-7)

Factoring y2-10y+21 Step-1 : Multiply the coefficient of the first term by the constant 1 • 21 = 21 Step-2 : Find two factors of 21 whose sum equals the coefficient of the middle term, which is -10 . -21 + -1 = -22 -7 + -3 = -10 That's itStep-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -7 and -3 y2 - 7y - 3y - 21Step-4 : Add up the first 2 terms, pulling out like factors : y • (y-7) Add up the last 2 terms, pulling out common factors :

Factoring y2-10y+21 Step-1 : Multiply the coefficient of the first term by the constant 1 • 21 = 21 Step-2 : Find two factors of 21 whose sum equals the coefficient of the middle term, which is -10 . -21 + -1 = -22 -7 + -3 = -10 That's itStep-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -7 and -3 y2 - 7y - 3y - 21Step-4 : Add up the first 2 terms, pulling out like factors : y • (y-7) Add up the last 2 terms, pulling out common factors : 3 • (y-7)

Answer 2

Answer:

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