Math, asked by mykartik663, 6 hours ago

Factorise y^2 + 2y - 120 with whole solution ​

Answers

Answered by 06kalepurvesh
1

Answer:

The first term is, y2 its coefficient is 1 .

The middle term is, +2y its coefficient is 2 .

The last term, "the constant", is -120

Step-1 : Multiply the coefficient of the first term by the constant 1 • -120 = -120

Step-2 : Find two factors of -120 whose sum equals the coefficient of the middle term, which is 2 .

-120 + 1 = -119

-60 + 2 = -58

-40 + 3 = -37

-30 + 4 = -26

-24 + 5 = -19

-20 + 6 = -14

-15 + 8 = -7

-12 + 10 = -2

-10 + 12 = 2 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and 12

y2 - 10y + 12y - 120

Step-4 : Add up the first 2 terms, pulling out like factors :

y • (y-10)

Add up the last 2 terms, pulling out common factors :

12 • (y-10)

Step-5 : Add up the four terms of step 4 :

(y+12) • (y-10)

Which is the desired factorization

Answered by 06kalepurvesh
1

Answer:

The first term is, y2 its coefficient is 1 .

The middle term is, +2y its coefficient is 2 .

The last term, "the constant", is -120

Step-1 : Multiply the coefficient of the first term by the constant 1 • -120 = -120

Step-2 : Find two factors of -120 whose sum equals the coefficient of the middle term, which is 2 .

-120 + 1 = -119

-60 + 2 = -58

-40 + 3 = -37

-30 + 4 = -26

-24 + 5 = -19

-20 + 6 = -14

-15 + 8 = -7

-12 + 10 = -2

-10 + 12 = 2 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and 12

y2 - 10y + 12y - 120

Step-4 : Add up the first 2 terms, pulling out like factors :

y • (y-10)

Add up the last 2 terms, pulling out common factors :

12 • (y-10)

Step-5 : Add up the four terms of step 4 :

(y+12) • (y-10)

Which is the desired factorization

Answered by 06kalepurvesh
1

Answer:

The first term is, y2 its coefficient is 1 .

The middle term is, +2y its coefficient is 2 .

The last term, "the constant", is -120

Step-1 : Multiply the coefficient of the first term by the constant 1 • -120 = -120

Step-2 : Find two factors of -120 whose sum equals the coefficient of the middle term, which is 2 .

-120 + 1 = -119

-60 + 2 = -58

-40 + 3 = -37

-30 + 4 = -26

-24 + 5 = -19

-20 + 6 = -14

-15 + 8 = -7

-12 + 10 = -2

-10 + 12 = 2 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and 12

y2 - 10y + 12y - 120

Step-4 : Add up the first 2 terms, pulling out like factors :

y • (y-10)

Add up the last 2 terms, pulling out common factors :

12 • (y-10)

Step-5 : Add up the four terms of step 4 :

(y+12) • (y-10)

Which is the desired factorization

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