factorise y^2 - 2y - 15
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Answered by
50
Answer:
y²-2y-15
y²+3y-5y-15
y( y+3) -5( y+3)
= (y-5) (y+3)
Answered by
2
y^2 - 2y - 15
After splitting the middle term appropriately,
y^2 - 5y + 3y - 15
Taking out the common factors,
y ( y - 5 ) + 3 ( y - 5 )
Again taking out the common term,
( y - 5 ) ( y + 3 )
⟶Thank You
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