Question

factorise=y^2-2y-3
please send with explanation ​

Answer 1

Answer:

factorise=y^2-2y-3

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Answer 2

Step-by-step explanation:

$y ^ { 2 } -2y-3$

Factor the expression by grouping. First, the expression needs to be rewritten as y^2+ay+by-3. To find a and b, set up a system to be solved.

$a+b=-2 \\ ab=1\left(-3\right)=-3$

$Rewrite \: y^{2}-2y-3 \\ as \left(y^{2}-3y\right)+\left(y-3\right).$

$\left(y^{2}-3y\right)+\left(y-3\right)$

$\left(y-3\right)\left(y+1\right)$