..factorise y^2+2y-48
Answers
Answered by
40
Hey dear!
Here is yr answer.....
=> y² + 2y -48
=> y² + 8y - 6y -48
=> y(y+8) -6(y+8)
=> (y+8) (y-6)
Hope it hlpz...
Here is yr answer.....
=> y² + 2y -48
=> y² + 8y - 6y -48
=> y(y+8) -6(y+8)
=> (y+8) (y-6)
Hope it hlpz...
Answered by
20
Hey friends!!
Here is your answer↓
Factorising by middle term spilts method:-
First do the prime factorisation of 48×1=2×2×2×2×3.
After that what we do with prime factors that on adding it is 2y and by multiplying it is 48.
Therefore we do this
8y-6y=2y
and 8×6=48.
A/Q
→y²+2y-48
= y²+8y-6y-48.
= y(y+8)-6(y+8).
= (y-6) (y+8).
☺☺☺ Hope it is helpful for you ✌✌✌.
Here is your answer↓
Factorising by middle term spilts method:-
First do the prime factorisation of 48×1=2×2×2×2×3.
After that what we do with prime factors that on adding it is 2y and by multiplying it is 48.
Therefore we do this
8y-6y=2y
and 8×6=48.
A/Q
→y²+2y-48
= y²+8y-6y-48.
= y(y+8)-6(y+8).
= (y-6) (y+8).
☺☺☺ Hope it is helpful for you ✌✌✌.
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