Question

factorise y^2-√3y-6​

Answer 1

Answer:

y^2-√3y-6 = 0

y² -√3y = 6

y² -√3y + (√3/2)² = (√3/2)² +6

(y - √3/2)² = 6 + 3/4

(y - √3/2)² = 27/4

y - √3/2 = plus minus√27/2

y = √3/2 +√27/2. or y = √3/2 - √27/2

y = (√3+√27)/2 or y = (√3-√27)/2