Math, asked by akansh54, 19 days ago

factorise: y^2+3zx-2xy-4yz​

Answers

Answered by AdiSTo
1

Answer:

(2x - y)(4z - y)

Step-by-step explanation:

 {y}^{2}  + 8zx - 2xy - 4yz

 =   {y}^{2}  - 2xy + 8zx - 4yz

 = y(y - 2x) + 4z(2x - y)

 =  - y(2x - y) + 4z(2x - y)

 = (2x - y)(4z - y)

Hope it helps.

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Answered by ashokfarsanmart
0

Answer:

Answer in this picture

Step-by-step explanation:

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