Question

Factorise :

y^2-7y+12​

Answer 1

Answer :

• Zeroes of the polynomial are 3 and 4 respectively.

Given :

• A quadratic polynomial.

To Find :

• Zeroes of the polynomial.

Solution :

Write the equation first

• y² - 7y + 12

Split the middle term

• y² - 4y - 3y + 12

Take common

• y (y - 4) - 3 (y - 4)

Rearrange together

• (y - 3) (y - 4)

Equate with 0

• y - 3 = 0

⇒ y = 3

• y - 4 = 0

⇒ y = 4

_____________

Hence, the zeroes of the polynomial are 3 and 4 respectively.

Answer 2

Answer:

above your answer

with full explaination..