Factorise y^2-ky-2k^2
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Answered by
10
Solution :
Now, y² - ky - 2k²
= y² + (1 - 2) ky - 2k²
= y² + ky - 2ky - 2k²
= y (y + k) - 2k (y + k)
= (y + k) (y - 2k) ,
which is the required factorization.
Answered by
15
Answer:
Hope you got each step dear.. First I just multiply the coefficients of last two terms and thought about how they can result into -1 ...and the rest is as shown...
Mark it as brainliest dear if you find it helpful...
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