Question

Factorise:y^3+125 jaldi karo​

Answer 1

Step-by-step explanation:

${y}^{3} + 125 \\ = {(y)}^{3} + {(5)}^{3} \\ { {(x)}^{3} + {(y)}^{3} = {(x + y)}^{3} ( {x}^{2} - xy + \\ {y}^{2} )} \\ = {(y + 5)}^{3} ( {y}^{2} - 5y + 25)$

Answer 2

$\huge{\underline{\underline{\mathcal{\pink{ANSWER}}}}}$

${y}^{3} + 125$

$= {y}^{3} + {5}^{3}$

using identity

${a}^{3} + {b}^{3} = (a + b)( {a}^{2} + {b}^{2} - ab)$

we get

$(y + 5)( {y}^{2} + {5}^{2} - 5y)$

$(y + 5)( {y}^{2} - 5y + 25)$

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