Question

factorise:y^3-18y^2+108y-216​

Answer 1

Answer:

${y}^{3} - {18y}^{2} + 108y - 216 \\ \\( use \: identity) \\ = > {a}^{3} - 3 {a}^{2} b + 3a {b}^{2} - {b}^{3} = ( {a + b})^{3} \\ \\ = > {y}^{3} - {18y}^{2} + 108y - {6}^{3} \\ \\ a = y \: and \: b = 6 \\ \\ answer = > {(y - 6)}^{3}$

Answer 2

Answer:

comparing with the identity a^3-3a^2b+3ab^2-b^3

Step-by-step explanation:

=y^3- 3(y)^2(6)+3(y)(6^2)-6^3

=(y - 6 )^3