factorise y^3-3y^2-y+3
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Answered by
1
= y^3 - 3y^2 - y + 3
= y^2 (y-3) - 1(y-3)
= (y^2 - 1) (y-3)
= (y^2 - 1^2) (y-3)
= (y+1) (y-1) (y-3)
Hope it's helpful to u.
= y^2 (y-3) - 1(y-3)
= (y^2 - 1) (y-3)
= (y^2 - 1^2) (y-3)
= (y+1) (y-1) (y-3)
Hope it's helpful to u.
Answered by
2
y^2(y-3)-(y-3)
(y-3)(y+1)(y-1)
(y-3)(y+1)(y-1)
Anonymous:
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