Factorise : y^3-7y+6
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Multiple 6 with y³ = 6y³
Then find the factors of 6y³
= 6×1
= 2×3
When you do the operation of 6 + 1 you get 7. Which will be the middle term of the question.
Hence, the equation would be =
y³ + 6y + y + 6
Take things common.
y ( y+ 6 ) 1 ( y + 6 )
= ( y + 6 ) ( y + 1 )
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