Question

factorise y^3+y^2-y-1​

Answer 1

Answer:

(y+1)(y+1)(y−1)

Step-by-step explanation:

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Answer 2

Answer:

$=(y + 1)^{2} (y - 1)$

Step-by-step explanation:

$y^{3}$ $+y^{2}$ $-y$ $-1$

$=y^{2} (y + 1) -1(y + 1)$

$=(y + 1)(y^{2} - 1)$

$=(y + 1)(y + 1)(y - 1)$  [∵ $a^{2} - b^{2} = (a + b)(a - b)$]

$=(y + 1)^{2} (y - 1)$