Question

factorise y^4+4y^2-32

Answer 1

=y^4+8y^2-4y^2-32
=y^2(y^2+8) -4(y^2-8)
=(y^2+8) (y^2-4)

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Answer 2

Answer:

(y2+4) • (y2-8)

Step-by-step explanation:

(1): "y2" was replaced by "y^2". 1 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

((y4) - 22y2) - 32

STEP

2

:

Trying to factor by splitting the middle term

2.1 Factoring y4-4y2-32

The first term is, y4 its coefficient is 1 .

The middle term is, -4y2 its coefficient is -4 .

The last term, "the constant", is -32

Step-1 : Multiply the coefficient of the first term by the constant 1 • -32 = -32

Step-2 : Find two factors of -32 whose sum equals the coefficient of the middle term, which is -4 .

-32 + 1 = -31

-16 + 2 = -14

-8 + 4 = -4 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -8 and 4

y4 - 8y2 + 4y2 - 32

Step-4 : Add up the first 2 terms, pulling out like factors :

y2 • (y2-8)

Add up the last 2 terms, pulling out common factors :

4 • (y2-8)

Step-5 : Add up the four terms of step 4 :

(y2+4) • (y2-8)