Question

factorise. y cube +y square- y-1​

Answer 1

Answer:

$y^{3} +y^{2}-y-1\\ =y^{3} -y+y^{2}-1 \\=y(y^{2}-1)+1(y^{2}-1)\\=(y+1)(y^{2}-1)\\=(y+1)(y+1)(y-1)$

Step-by-step explanation:

Answer 2

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