Question

factorise (y power 4+ y power 2+1)​

Answer 1

Answer:

answer is

Step-by-step explanation:

y power 4+ y power 2+1)

y^4+y^2+1

=y^4+y^3

mark as brailiant answer

Answer 2

Answer:

$\bold\red{( {y}^{2} + 1 + y)( {y}^{2} + 1 - y)}$

Step-by-step explanation:

Given,

${y}^{4} + {y}^{2} + 1$

Breaking in squares,

we get,

$= ({( {y}^{2} )}^{2} + {1}^{2} ) + {y}^{2}$

Now,

we know that,

${a}^{2} + {b}^{2} = {(a + b)}^{2} - 2ab$

Therefore,

we get,

$= {( {y}^{2} + 1) }^{2} - 2 \times {y}^{2} \times 1 + {y}^{2}$

Therefore,

we get,

$= {( {y}^{2} + 1) }^{2} - 2 {y}^{2} + {y}^{2} \\ \\ = {( {y}^{2} + 1) }^{2} - {y}^{2} \\ \\ = {( {y}^{2} + 1) }^{2} - {(y)}^{2}$

Now,

we know that,

${a}^{2} - {b}^{2} = (a + b)(a - b)$

Therefore,

we get,

$= ( {y}^{2} + 1 + y)( {y}^{2} + 1 - y)$