Factorise
y sqare 8y+16
shadowsabers03:
Symbol of 8y.
Answers
Answered by
2
Answer.
y2 - 8y + 16 = 0
y2 - 4y - 4y + 16 = 0
y(y-4) -4 (y-4) = 0
(y-4) (y-4) = 0
y = 4 or y = 4.
Answered by
1
Answer:
Step-by-step explanation:
Y^2-8y+16
Let the two roots of the equation be p and q respectively.
Therefore, product of roots(p x q) must be equal to the product of the first and last terms,ie, 16 x 1 = 16.
And the sum of the two roots must be equal to the middle term,ie, 8.
=> p x q = 16 and p + q = 8.
=> p=4, and q= 4 [4 x 4=16, 4 + 4 = 8]
=> y^2 - 4y - 4y + 16= 0
=> y(y-4) - 4(y-4)=0
=>(y-4) (y-4) =0
=> y=4, y=4
Therefore, there are two equal roots for this equation, 4 and 4.
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