factorise y2+2y-3 plz send fast
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Answer:
y 2+3y−y−3=0
⇒y(y+3)−1(y+3)=0
Step-by-step explanation:
taking (y+3)common,
⇒(y+3)(y−1)=0
∴ y+3=0 OR y−1=0
y=−3 OR y=1
Hope this helps you
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