Math, asked by kalluldeka, 3 days ago

factorise (y²+2y-3)÷(y-1)​

Answers

Answered by abhi8190
0

Answer:

y +3

Step-by-step explanation:

The first term is, y2 its coefficient is 1 .

The middle term is, +2y its coefficient is 2 .

The last term, "the constant", is -3

Step-1 : Multiply the coefficient of the first term by the constant 1 • -3 = -3

Step-2 : Find two factors of -3 whose sum equals the coefficient of the middle term, which is 2 .

-3 + 1 = -2

-1 + 3 = 2 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -1 and 3

y2 - 1y + 3y - 3

Step-4 : Add up the first 2 terms, pulling out like factors :

y • (y-1)

Add up the last 2 terms, pulling out common factors :

3 • (y-1)

Step-5 : Add up the four terms of step 4 :

(y+3) • (y-1)

Which is the desired factorization

Cancel out (y-1) which appears on both sides of the fraction line.

Final result :

y + 3

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