Question

factorise
(y²–3y)² – 5(y²–3y) - 50.​

Answer 1

Step-by-step explanation:

\implies⟹ Let (y²-3y) = x

\implies⟹ (y²-3y)²- 5(y²-3y)- 50 = x² - 5x - 50

\implies⟹ x² -10x + 5x - 50

\implies⟹ x(x - 10) +5(x - 10)

\implies⟹ (x - 10) (x + 5)

\implies⟹ (y² -3y - 10) (y² -3y + 5)

\implies⟹ [y² - 5y + 2y - 10] (y² -3y + 5)

\implies⟹ y(y - 5) +2(y - 5)] (y² -3y + 5)

\implies⟹ (y - 5) (y + 2) (y² - 3y + 5)