Question

Factorise y2 + 4y + 4​

Answer 1

Answer:

y2 + 4y + 4 = 0

y2 + 2y + 2y + 4 = 0

y(y+ 2) + 2( y + 2)

(y + 2) (y+ 2) is your answer

Answer 2

Answer:

$\sf \: y^2−4y+3 \\ \\ \sf \: =y^2−y−3y+3 \\ \\ \sf=y(y−1)−3(y−1) \\ \\ \sf=(y−1)(y−3) \\ \\ \sf \: Hence, \: the \: answe r \: is \\ \\   \sf(y−1)(y−3).$