Question

Factorise Y2-6y-135

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$y^2 - 6y - 135 = (y+9)(y-15)$

Solution:

Given that,

We have to factorize the given

$y^2 - 6y - 135$

We have to write as product of two factors

From given,

$y^2 - 6y - 135 \\\\Split\ the\ middle\ term \\\\y^2 + 9y - 15y - 135 \\\\\mathrm{Break\:the\:expression\:into\:groups} \\\\\left(y^2+9y\right)+\left(-15y-135\right) \\\\\mathrm{Factor\:out\:}y\mathrm{\:from\:}y^2+9y \\\\y(y + 9) + (-15y - 135) \\\\ \mathrm{Factor\:out\:}-15\mathrm{\:from\:}-15y-135\mathrm{:\quad }\\\\y\left(y+9\right)-15\left(y+9\right)\\\\\mathrm{Factor\:out\:common\:term\:}y+9\\\\\left(y+9\right)\left(y-15\right)$

Thus the given expression is written as product of two factors

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