Question

factorise ( y²+6y-216 =0)​

Answer 1

y square +18y-12y-216=0

y(y+18) -12(y+18)=0

(y-12)(y+18)=0

y= 12,18

Answer 2

(y - 12)(y + 18) = 0 is the factored form

Solution:

Given that,

$y^2 + 6y - 216 = 0$

We have to factorize the given expression

We have to write as a product of factors

Split the middle term

$y^2 - 12y + 18y - 216 = 0\\\\Break\:the\:expression\:into\:groups\\\\\left(y^2-12y\right)+\left(18y-216\right) = 0\\\\\mathrm{Factor\:out\:}y\mathrm{\:from\:}y^2-12y\\\\y(y - 12) + (18y-216) = 0\\\\\mathrm{Factor\:out\:}18\mathrm{\:from\:}18y-216\\\\y\left(y-12\right)+18\left(y-12\right) = 0\\\\\mathrm{Factor\:out\:common\:term\:}y-12\\\\\left(y-12\right)\left(y+18\right) = 0$

Thus the given expression is factored

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