Question

factorise y2+8xz+4yz by grouping

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Answer 1

Answer:

y ²+8zx−2xy−4yz=(y² −2xy)+(8xz−4yz)

=y(y−2x)−4z(−2x+y)=y(y−2)−4z(y−2x)

= (y−2x)(y−4z)

hope it helps.

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