Question

factorise y2-8y+16

Please Give Me Answer

Answer 1

Answer:

Step-by-step explanation:

y×y-4y-4y+16

y(y-4)-4(y-4)

(y-4)(y-4) is the answer

Answer 2

Answer:

After factorizing the equation we get = $(y-4)^{2}$

Step-by-step explanation:

There are 2 method of solving such equation:-

1) Grouping Method:-

Step 1:- First use the sum product pattern we get,

$y^{2} -8y+16$

$y^{2} -4y-4y+16$

Step 2:- Not lets take common factor from two pairs.

$y(y-4)-4(y-4)$

Step 3:- Now lets rewrite the factored forms,

$(y-4)(y-4)$

Step 4:- At the end we will combine it as a square,

$(y-4)^{2}$

Hence the answer is $(y-4)^{2}$.

2) Perfect Square Trinomial Method:-

Step 1:- First we will change 16 in square form

$16=4^{2}$

Now the new equation is $y^{2} -8y+4^{2}$

Step 2:- As the middle term is the product of first term and third term we can write it as,

$8y=2*y*4$

Step 3:-  Now we will rewrite the polynomial,

$y^{2} -2*y*4+4^{2}$

Step 4:- Now according to the rule $a^{2} -2ab+b^{2}$$=(a-b)^{2}$, where a = y and b = 4, we get

$(y-4)^{2}$.

Hence the answer is $(y-4)^{2}$.