Question

factorise y² - y - 6 by using factor theorem​

Answer 1

Answer:

${y}^{2} - (3 - 2)y - 6 \\ = {y}^{2} - 3y + 2y - 6 \\ = y(y - 3) + 2(y - 3) \\ = (y + 2)(y - 3)$

That's how you do it. HOPE ITS HELPFUL.