Question

factorise
ý3 -23y2 +142y-120​

Answer 1

Question:-

Factorise the polynomial.

Solution:-

$\sf {y}^{3} - 23 {y}^{2} + 142y - 120$

$\sf = {y}^{3} - { y }^{2} - 22 {y}^{2} + 22y+ 120y - 120$

$\sf = {y}^{2} (y - 1) - 22y(y - 1) + 120(y - 1)$

$\sf = (y - 1) ({y}^{2} - 22y + 120)$

$\sf = (y - 1) ({y}^{2} - 12y - 10y + 120)$

$\sf = (y - 1) (y(y - 12)- 10(y - 12))$

$\sf = (y - 1)(y - 10)(y - 12)$

Hence, the factorised form is (y-1)(y-10)(y-12)

Answer 2

Answer:

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Step-by-step explanation:

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