factorise y³-23y²+142y-120
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put y =1 ,
1³-23(1)²+142(1)-120=1+22-23=23-23=0
so,(y-1)is a factor .now divide y³-23y²+142y-120
we get, y²-22y+120
now factorise y²-22y+120=0
y²-12y-10y+120=0
y(y-12)-10(y-12)=0
(y-12)(y-10)=0
or y³-23y²+142y-120=(y-1)(y-12)(y-10)
1³-23(1)²+142(1)-120=1+22-23=23-23=0
so,(y-1)is a factor .now divide y³-23y²+142y-120
we get, y²-22y+120
now factorise y²-22y+120=0
y²-12y-10y+120=0
y(y-12)-10(y-12)=0
(y-12)(y-10)=0
or y³-23y²+142y-120=(y-1)(y-12)(y-10)
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