Factorise :
y³ - 2y² - 29y - 42
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Solution:
Find one factor by grouping
y³ - 2y² - 29y - 42
= y³ + 5y² + 6y - 7y - 35y - 42
= y (y² + 5y + 6) - 7 (y² + 5y + 6)
= (y - 7) (y² + 5y + 6)
= (y - 7) (y² + 2y + 3y + 6)
= (y - 7) [ y (y + 2) + 3 (y + 2) ]
= (y - 7) (y + 2) (y + 3)
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