Question

Factorise y³-6y²+3y+10​

Answer 1

Step-by-step explanation:

${y}^{3} - 6 {y}^{2} + 3y + 10 \\ \\ = {y}^{2} (y + 1) -7y (y + 1) + 10 (y +1 ) \\ \\ = (y + 1)( {y}^{2} - 7y + 10) \\ \\ = (y + 1)(y {}^{2} - 5y - 2y + 10) \\ \\ = (y + 1)(y(y - 5) - 2(y - 5)) \\ \\ = (y + 1)(y - 5)(y - 2)$

For finding the factors of cubic polynomial u show check when it become zero

E.g. here at y=-1. is will give zero then (y+1) will one factor

Answer 2

Answer:

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Step-by-step explanation:

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