Question

factorise y³-y in linear polynomial​

Answer 1

Required Answer:-

Given To Factorise:

• y³ - y

Solution:

Given that,

= y³ - y

Taking y as common, we get,

= y(y² - 1)

We know that,

→ a² - b² = (a + b)(a - b)

So, y(y² - 1),

= y[(y)² - (1)²]

= y(y + 1)(y - 1)

→ Hence, the factorised form of the given polynomial is y(y + 1)(y - 1)

Answer:

• y(y + 1)(y - 1)

Identity Used:

• a² - b² = (a + b)(a - b)

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