Question

factorise y3+y2-y-1​

Answer 1

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$y {}^{3} + y {}^{2} - y - 1 \\ y {}^{2} (y + 1) - 1(y + 1) \\ (y {}^{2} - 1)(y + 1) \\ \\ now.. \\ y {}^{2} - 1 = 0 \\ y {}^{2} = 1 \\ y = \sqrt{1} \\ y = 1 \\ \\ \\ and \\ \\ \\ y + 1 = 0 \\ y = - 1$

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Answer 2

Answer:

$y3 + y2 - y - 1$

$=> y4 - 1$

$=> y = \frac{1}{4}$

hence "y" = 1/4