Question

Factorise y³+y²-y-1​

Answer 1

Answer:

Hope it helps you

Step-by-step explanation:

Answer 2

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Explanation:

${y}^{3} + {y}^{2} - y - 1 = 0$

The given equation is a cubic polynomial as the highest degree is 3.So ,the factor comes will also be 3.

$= > {y}^{2} (y + 1) - 1(y + 1) = 0$

$= > ( {y}^{2} - 1)(y + 1)$

Here ,y^2-1 can also be written as ${y}^{2} - {1}^{2}$ which is an identity

Identity used here :

$\bold{\boxed{(x + y)(x - y) = {x}^{2} - {y}^{2} }}$

$\bold{= > (y + 1)(y - 1)(y + 1)}$

Therefore ,the factor of y³+y²-y-1 is (y+1)(y-1)(y+1)