Question

Factorise y³+y²-y-1 and dividing​

Answer 1

Step-by-step explanation:

The value of y3+y2−y−1 is

y3−y2+2y2−2y+y−1

=y2(y−1)+2y(y−1)+1(y−1)

=(y−1)(y2+2y+1)

=(y−1)[y2+y+y+1]

=(y−1)[y(y+1)+1(y+1)]

=(y−1)(y+1)2

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Answer 2

Answer:

i hope it helps

Step-by-step explanation:

question y²×y-y-1

1. =y²×y+y²-y-1

2. =y²(y+1)-1(y+1)

3. =(y+1)(y²-1)