Question

Factorise:- z(5z^2 -80) ÷ 5z(z+4)​

Answer 1

Step-by-step explanation:

Solution:-

$\frac{z(5 {z}^{2} - 80) }{5z(z + 4)} = \frac{5z( {z}^{2} - 16) }{5z(z + 4) } \\ = \frac{5z(z + 4)(z - 4)}{5z(z + 4)} \\ = z - 4 \\ the \: formula \: used \: here \\ ( {x}^{2} - {y}^{2} ) = (x + y)(x - y)$