Question

factorise z
$z ^{2} + 12z + 27$
+12z+27​

Answer 1

Answer:

z^2 + 12z^1 + 27 + 12z^1 +27

12z^1 + 27 + ( z^2)

Step-by-step explanation:

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Answer 2

$\rm{Question:-}$

• $\sf \: {z}^{2} + 12z \: + 27$

$\rm{Solution:-}$

Let us first find two numbers whose sum is 12 and product us 27.

Since the product is positive, therefore, both factors of 27 will be either positive or negative.

But the sum is positive so both the factors of 27 will be positive.

Required factors of 27 are 9 and 3.

So,

$\sf \: {z}^{2} + 12z \: + 27 \\ = \: \sf {z}^{2} + 9z \: + 3z \: + 27 \\ = \sf \: z(z \: + 9) \: + 3(z + 9) \\ = \sf \: (z + 9) \: (z + 3)$

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